Question

in an ap the sum of first ten terms is 150 and the sum of its next 10 terms is 550.

there is no minus here pls help

Answer 1

Answer:

the correct answer is 600

Answer 2

Answer:

d=-4 and a=3

Step-by-step explanation:

The sum of the first n terms of an AP is

Sn=(n/2)[2a+(10-1)d]

n=10, S10=-150

-150=(10/2)[2a+(10-1)d]

-150=5[2a+9d]

Dividing through by 5,

-30=2a+9d______(1)

Given sum of its next 10 terms is -550

n=10,Sn=-550

Here a=a+10d

-550=(10/2)[2(a+10d)+(10-1)d]

-550=5[2a + 29d]

Dividing through by 10,

-110=2a+29d_____(2)

Solving (1) and (2) we get

d=-4 and a=3.

Hope it helps you...

Pls mrk me brainliest...