In an ap the sum of first term third term and fifth term is 39
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The sum of the first 30 terms is 2460.
Step-by-step explanation:
given that:
a₃=32
or a+2d=32 ---------------(i)
a₅=40
or a+4d=40 ----------------(ii)
On subtracting (i) from (ii), we get 2d=8
or d=4
Now,
a+2d=32
a+8=32
a=24
Then sum of first 30 terms :
S₃₀=[2a+(n-1)d]
S₃₀=
S₃₀=15(48+116)
S₃₀=15*164
S₃₀=2460.
Hence, the sum of first 30 terms in 2460.
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