In an ap the sum of four terms is 20and the sum of their squares is 120 find the four terms
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Step-by-step explanation:
a+a+d+a+2d+a+3d = 20
4a + 6d = 20
2a + 3d = 10 -----(1)
a² + (a+d)² + (a+2d)² + (a+3d)² = 120
a²+a²+2ad+d²+a²+4ad+4d²+a²+6ad+9d² = 120
4a²+12ad+14d² = 120
(2a+3d)² + 5d² = 120
5d² = 120-100 = 20
d² = 4 , d = 2
2a + 6 = 10 , 2a = 4 , a = 2
The terms are 2 , 4 , 6 & 8
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