in an AP the sum of its first ten terms is 150 and the sum next m terms is 550 find the P
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AP is - 3 , 1 , 5 , ................
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in an AP the sum of its first 10 is 150 and the sum of next 10 terms is 550 find the AP
S₁₀ = 150
S₂₀ = 150 + 550 = 700
S₁₀ = (10/2)(2a + 9d) = 150
=> 2a + 9d = 30
S₂₀ = (20/2)(2a + 19d) = 700
=> 2a + 19d = 70
=> 10d = 40
=> d = 4
2a + 9d = 30
=> 2a + 9*4 = 30
=> a = - 3
a = - 3 d = 4
AP is - 3 , 1 , 5 , ................
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