in an AP the sum of n terms is 1/2(5n^2+3n).find its 40th term
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Answered by
2
T40=1/2(5*4.^2 +3*40)
T40=1/2(20^2 +120)
T40=1/2(400+120)
T40=1/2(520)
T40=260
The 40th term of AP is 260
T40=1/2(20^2 +120)
T40=1/2(400+120)
T40=1/2(520)
T40=260
The 40th term of AP is 260
satyavika:
thanks
Answered by
1
The 40term is 199 which is correct
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