In an AP the sum of the first ten terms is -150 and the sim of its next ten terms is -550 . Find the AP ?
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Is AP is 3,-1,-5.... i.e. a = 3 d =-4
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Final result :
AP is 3,-1,-5.. ...
a = 3 d = -4 where terms have usual meanings.
1) S (10) = Sum of first 10 terms =-150
2) S(20)-S(10) = Sum of next 10 terms =-550
S (n) = n/2[2a +(n-1)d]
a : First term
d: common difference
n: number of terms
Hope, you understand my answer.
AP is 3,-1,-5.. ...
a = 3 d = -4 where terms have usual meanings.
1) S (10) = Sum of first 10 terms =-150
2) S(20)-S(10) = Sum of next 10 terms =-550
S (n) = n/2[2a +(n-1)d]
a : First term
d: common difference
n: number of terms
Hope, you understand my answer.
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