in an ap the third term is 21 and the nineth term is 39 then find tewelth term
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Answered by
0
Answer:
a+8d=39
a+2d=21
subtract them
6d=18
d=3
then a=15
12th term = a+11d
= 15+11(3)
=48
Answered by
3
EXPLANATION.
=> The third term of an Ap = 21
=> The ninth term of an Ap = 39.
To find the 12th term.
Formula of Nth term of an Ap
=> An = a + ( n - 1 ) d.
=> a + 2d = 21 .......(1)
=> a + 8d = 39 ......(2)
From equation (1) and (2) we get,
=> - 6d = - 18
=> d = 3
Put the value of d = 3 in equation (1)
we get,
=> a + 2(3) = 21
=> a + 6 = 21
=> a = 15
Therefore,
12 th term of an Ap
=> a + 11d
=> 15 + 11(3)
=> 15 + 33
=> 48
12th term of an Ap = 48.
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