in an AP the third term is equal to five times the sixth term. the second term is lesser by 3 than twice the fourth term. find the term of AP
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let a be first term and d be c.d of an ap.
so, a3= 5(a+ 5d)
a3=5a+25d
a+2d=5a+25d.
4a= -23d
a= -23/4
also, a2= 2a4 -3
a+d=2a+6d-3
a+5d=3
-23/4 +5d =3
d= -4
so sequence are 23,19,15,,,,,,,,
so, a3= 5(a+ 5d)
a3=5a+25d
a+2d=5a+25d.
4a= -23d
a= -23/4
also, a2= 2a4 -3
a+d=2a+6d-3
a+5d=3
-23/4 +5d =3
d= -4
so sequence are 23,19,15,,,,,,,,
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