Question

in an ap thrise the second term is equelent to eighth term and the sum of the fourth term and the seventh term is 9 grater then the ninth term find the AP soluti in steps​

Answer 1

Answer:

3a2 =a8

3(a +d) = a +7d

3a +3d = a +7d

2a =4d

a = 2d......(1)

a4 + a7 = 9 + a9

a + 3d +a +6d = 9 + a + 8d

2a+9d = 9 +a +8d

a + d = 9.....(2)

put the value of a from (1) in (2)

2d +d=9

3d = 9

d = 3

a = 2d = 6

AP:

6, 9, 12, 15...