In an AP, tn represents the nth term. t, and tz are
two-digit numbers such that their digits are the
same, but their positions are interchanged.
If tz – t1 = -18 and the sum of the digits of ti is 8,
then find the value of
a. 3.5
b. 4.5
C. 5.5
d. 6.5
Answers
Answer:
4.5
Step-by-step explanation:
the sum of digits of time is 4.5
Given : ti and tz are two-digit numbers such that their digits are the same, but their positions are interchanged.
tz - ti = -18
sum of the digits of ti is 8,
To Find : Value of Digits
Solution:
ti and tz are two-digit numbers such that their digits are the same, but their positions are interchanged.
ti = AB => value = 10A + B
tz = BA => Value = 10B + A
tz - ti = -18
10B + A - (10A + B) = - 18
=> 9B - 9A = -18
=> B - A = - 2
=> A - B = 2
sum of the digits of ti is 8
=> A + B = 8
2A = 10
=> A = 5
& B = 3
ti = 53
tz = 35
Digits are 3 & 5
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