In an apartment 2+5+8+11....which term is 65?
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given sequence forms AP with common difference 3 hence the 65th term of this sequence will be a+64d=2+64*3=194
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Answered by
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a=2
d=3
an=65
a+(n-1)d=an
2+(n-1)×3=65
2+3n-3=65
2+3n=65+3
2+3n=68
3n=68-2
3n=66
n=66/3=22
THEREFORE 22nd term is 65
HOPE IT HELPS YOU...
d=3
an=65
a+(n-1)d=an
2+(n-1)×3=65
2+3n-3=65
2+3n=65+3
2+3n=68
3n=68-2
3n=66
n=66/3=22
THEREFORE 22nd term is 65
HOPE IT HELPS YOU...
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