In an apartment the first term is -4 the last term is 29 and the sum of all its term is 150 find its common difference
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If l is the last term, a is the first term and n is the number of terms then
sum=n/2×(a+l)
150=n/2×(-4+29)
150=25×n/2
n=12
l= a+(n-1)d
29=-4+ (12-1)d
29= -4+11d
11d=29+4
11d=33
d=3
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