Question

In an apparatus, the electric field was found to oscillate with an amplitude of 18 V/m. The magnitude of the oscillating magnetic field will be(a) 4 × 10⁻⁶ T(b) 6 × 10⁻⁸ T(c) 9 × 10⁻⁹ T(d) 11 × 10⁻¹¹ T

Answer 1

Answer:

B) 6 × 10⁻⁸ T

Explanation:

Amplitude of the apparatus = 18 V/m (Given)

Thus, E0 = 18 V/m

Relation between Eo and Bo -

B0 = E0/C - wherein

E0 is the electric field amplitude,  B0 is the magnetic field amplitude  and C is the speed of light in vacuum. Thus following the equation -

Oscillating magnetic field will be -

= 18/ 3 × 10⁸

= 6 × 10⁻⁸ T

Thus, the magnitude of the oscillating magnetic field will be 6 × 10⁻⁸ T

Answer 2

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In an apparatus, the electric field was found to oscillate with an amplitude of 18 V/m. The magnitude of the oscillating magnetic field will be(a) 4 × 10⁻⁶ T

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