Question

in an Apple sum of first 3rd term and 5th term, 39 and sum of 4rth and6th term 51 find the 10th term ofAP

Answer 1

Third term = a+2d
5th term = a+4d

3rd + 5th term = 39
a+2d+a+4d =39
2a+6d = 39...........(i)

Fourth term = a+3d
Sixth term = a+5d

4th + 6th term = 51
a+3d+a+5d = 51
2a+8d = 51.........(ii)

Substract (i) -(ii)

2a + 6d = 39
2a + 8d = 51
- - -
______________
-2d = -12

d = 6

Put this value on eqn. (i)

2a + 6d = 39
2a +6(6)= 39
2a = 3
a = 3/2

Tenth term = a+9d
= 3/2 + 54
= (3+108)/2
= 111/2

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