Question

In an arithemetic sequence 5th term 23 and 9th term is 39 find common difference and 14th term

Answer 1

Answer:

59

Step-by-step explanation:

Let the first team be a ;

and the common difference be r;

therefore 2nd term = a + r =$a{2}$;

a3= a+ 2r;

a4= a+3r;

a5= a+ 4r= 23;

a9 = a+8r = 39;

solving these two equations= r= 4; a= 23- 4r=23-16=7

therefore a14= a+ 13r= 7+ 13*4=7+52= 59