Question

in an arithmetic progress a= 100 and d= -1 then what is the value of t100=?
​

Answer 1

1

Step-by-step explanation:

a100=100+(100-1)-1

=100+(-99)

=100-99

=1

Answer 2

Answer:

1

Step-by-step explanation:

a1,a2,a3,....,a99,a100areinapLeta1=acommondifference,=da2=a+da3=a+2dsn=2n[2a1+(n−1)d]s100=2100[2a+99d]=50[2a+99d]=−1−−−−(1)eventermsa2,a4,...a100(n=50)a2=a+d,a4=a+2dcommondifference=(a+3d)−(a+d)Se=250[2