in an arithmetic progression, 1 term is 2 and last term is 20. the sum of all term is 396, then n =?
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Answer:
37.71
Step-by-step explanation:
Sn = n/2 (first terms + last terms) ∴ 396= n/2 (1+20) ∴ 396 x 2 = 21n ∴ n = 792/21 = 37.71
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