Question

In an arithmetic progression 25th term is ten times the first term.if 12th term is 41 the common difference is​

Answer 1

Step-by-step explanation:

Here, a = 5 and d = (15 - 5) = 10

The 31st term is given by

T31 = a + (31 - 1)d = a + 30d = 5 + 30 ⨯ 10 = 305

∴ Required term = (305 + 130) = 435

Let this be be the nth term.

Then Tn = 435

⇒ 5 + (n - 1) ⨯ 10 = 435

⇒ 10n = 440

⇒ n = 44

Hence, the 44th term will be 130 more than its 31st term.