in an arithmetic progression 6th term is one more than twice the third term the sum of the fourth and fifth term is five times the second term find 10th term
Answers
Answered by
1
Answer:29
Step-by-step explanation:
a+5d=2(a+2d)+1
a+5d=2a+4d+1
2a-a+4d-5d+1=0
a-d=-1--(1)
a+3d+a+4d=5(a+d)
2a+7d=5a+5d
5a-2a+5d-7d=0
3a-2d=0--(2)
(1)×2=2a-2d=-2--(3)
(2)-(3)
a=2
substitute in(1)
2-d=-1
d=2+1
d=3
tenth term = a+9d
x10=2+(9×3)
=2+27
=29
Similar questions