In an arithmetic progression 7, 11, 15, 19, ... , what is the sum upto 60 terms?
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Hi ,
7 , 11 , 15 , 19 , .... are in A.P
first term ( a ) = 7
common difference ( d ) = a2 - a1
d = 11 - 7 = 4
number of terms = n = 60
sum of n terms = Sn = n/2[ 2a + ( n - 1 )d ]
S60 = 60/2 [ 2 × 7 + ( 60 - 1 ) 4 ]
= 30 [ 14 + 59 × 4 ]
= 40 [ 15 + 236 ]
= 40 × 251
= 10040
S60 = 10040
Sum of 60 terms in given A. P = 10040
I hope this helps you.
:)
7 , 11 , 15 , 19 , .... are in A.P
first term ( a ) = 7
common difference ( d ) = a2 - a1
d = 11 - 7 = 4
number of terms = n = 60
sum of n terms = Sn = n/2[ 2a + ( n - 1 )d ]
S60 = 60/2 [ 2 × 7 + ( 60 - 1 ) 4 ]
= 30 [ 14 + 59 × 4 ]
= 40 [ 15 + 236 ]
= 40 × 251
= 10040
S60 = 10040
Sum of 60 terms in given A. P = 10040
I hope this helps you.
:)
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