Question

In an Arithmetic Progression, if a=28, d=-4, n=7, then an is:

Answer 1

an=a+(n-1)d

=28+(7-1)-4

=28+6(-4)

=28-24

=4

Answer 2

$Given \: in \: an \: Arithmetic \: progression ,$

$First \: term (a) = 28,$

$Common \: difference (d) = -4 \:and \:n = 7$

/* We know that, */

$\boxed { \pink{ n^{th} \: term (a_{n}) = a + (n-1)d }}$

$Here , a_{7} = a + (7-1)d$

$\implies a_{7} = 28 + 6 (-4)$

$= 28 - 24$

$= 4$

Therefore.,

$\red{ Value \: of \: a_{7} } \green { = 4 }$

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