Question

in an arithmetic progression of 4 numbers
1)sum of all four numbers is 82.
2)product of middle two terms is 420.
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find the four numbers
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Answer 1

0998653213480087531700963237853257973588566586 no. ha

Answer 2

Step-by-step explanation:

In the given problem, we need to find the sum of terms for different A.P.

So, here we use the following formula for the sum of n terms of an A.P.,

\(S_{n} = \frac{n}{2}\left [ 2a + \left ( n – 1 \right )d \right ]\)

Where; a = first term for the given A.P.

d = common difference of the given A.P. n = number of terms.

a2 – a1

= 46 – 50

= -4

Number of terms (n) = 10

First term for the given A.P. (a) = 50

So, using the formula we get,

S_{10} = \frac{10}{2}\left [ 2(50) + \left ( 10 – 1 \right )\left ( -4 \right )\right ]

= (5) [ 100 + (9)(-4) ]

= (5) [ 100 – 36 ]

= (6) [64]

= 320

Therefore, the sum of first 10 terms of the given A.P. is 320

hope it helps..!!