Question

In an arithmetic sequence 23rd term is 17 and 17th term is 23 find the 40th term

Answer 1

Answer:

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Step-by-step explanation:

let,

a be the first term

d be the common difference

A/Q

a+(23‐1)d=17

a+22d=17 ————1

a+(17‐1)d=23

a+16d=23 ———2

(1)‐(2)

a+22d‐a‐16d=17‐23

6d=‐6

d=‐1

putting the value of d=1 in equation 1

a+22×(‐1)=17

a‐22=17

a=17+22

a=39

Now,

a+(40‐1)d=39+39×(‐1)

=39‐39

=0

the 40th term is 0