In an arithmetic sequence ,if 'n'th term is m and 'm'th term is n .Prove that it's common difference is -1.
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Answer:
Step-by-step explanation:
d = common difference
Here, nth term,i.e,a(n)= a+(n-1)d =m [given]. ....(I)
and, mth term,i.e.,a(m)= a+(m-1)d =n [given]. ....(ii)
Subtracting (i) from (ii),we get-
(n-1)d-(m-1)d=m-n
or, d(n-1-m+1) = m-n
or, d(n-m) = -(n-m)
or, d = -1 ...
Hence, Proved...
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