Math, asked by GeneralZeuxis, 7 months ago

In an arithmetic sequence where the a1 = 6, an = 63, and d = 3. Find the value of n

Answers

Answered by Anonymous
1

Answer:

n = 20

Step-by-step explanation:

a = 6

d = 3

an = 63

n = ??

an = 63

a + (n - 1) d = 63

6 + (n - 1) 3 = 63

6 + 3n - 3 = 63

3n + 3 = 63

3n = 60

n = 20

Pls mark my answer as brainlist

Pls follow me

Answered by leanne02311
1

Step-by-step explanation:

t1 = a = 6; sn=63 ; d=3

:. Sn = n/2 + (n-1) d

:. 63= n/2+ (n-1) 3

:. 63= 2n-n ×3

:. 63/3= n

:. 21= n

:. the value of n is 21✌

Similar questions