In an arithmetic sequence where the a1 = 6, an = 63, and d = 3. Find the value of n
Answers
Answered by
1
Answer:
n = 20
Step-by-step explanation:
a = 6
d = 3
an = 63
n = ??
an = 63
a + (n - 1) d = 63
6 + (n - 1) 3 = 63
6 + 3n - 3 = 63
3n + 3 = 63
3n = 60
n = 20
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Answered by
1
Step-by-step explanation:
t1 = a = 6; sn=63 ; d=3
:. Sn = n/2 + (n-1) d
:. 63= n/2+ (n-1) 3
:. 63= 2n-n ×3
:. 63/3= n
:. 21= n
:. the value of n is 21✌
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