Question

In an army camp, there was provision for 850 men for 30 days. However, 750 men attended the camp. How long did the provision last?

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Answer 1

Answer:

34 days

Step-by-step explanation:

850 men = 30 days (Given)

Find the number of days the provision can last for 1 man:

1 man = 850 x 30 = 25500 days

Find the number of days the provision can last for 750 men:

1 man = 25500 days

750 men = 25500 ÷ 750 = 34 days

Answer: It can last for 34 days

Answer 2

Answer:

The days-long did the provision lasted is 34 Days.

Step-by-step explanation:

As per the data provided in the given question,

The given data is as follows,

In an army camp, there was provision for 850 men for 30 days,

And 750 men attended the camp.

We have to find how many days long did the provision last i.e.(x),

So we will multiply 850 into 30 is equal to 750 into x,

Further, we get

$850\times30=750x$

Now we will multiply 850 into 30

We get,

$25500=750x$

Now we will shift numerator 750 of RHS to the denominator of LHS

$\frac{25500}{750} =x$

We will cancel zero from the above equation

Further, we get

$\frac{2550}{75} =x$

Now we will divide both numerator and denominator by 5

We get,

$x=\frac{510}{15}$

Again we will divide both numerator and denominator by 5

We get,

$x=\frac{102}{3} \\x=34\;days$

The days-long did the provision last is 34 Days.