Math, asked by aryanbhushana1, 1 year ago

in an army camp there were provisions for 425 men for 30 days however ,375 men attended the camp .how long did the provisions last?

urgently send answers

Answers

Answered by JrmRockzzz
80
Men. Days
425. 30
375. x

This is inverse variation..the side of 'x' will be reversed..

425. x
375. 30

30*425/375=x
34=x

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Answered by gadakhsanket
34

Dear Student,

● Answer -

34 days

● Explanation -

Given that provisions were for 425 men for 30 days however, 375 men attended the camp.

Let x be no of days provisions last.

425 × 30 = 375 × x

x = 425 × 30 / 375

x = 34 days

Hence, provisions will last for 34 days to 375 days.

Thanks dear. Hope this helps you...

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