Math, asked by tapanalpana0100, 3 months ago

In an army camp there where provision for 425 men for 30 days how long did the provision last for 3 75 days. ​

Answers

Answered by vandana02250
0

Answer:

no of provisions for which last for 425 men = 30 days

no of days for which provisions last for 1 day = 30×425

=12750 days ( less men means more days)

no of days for which provisions last for 375 men =12750÷375

=34

hence provisions will last for 34 days for 375 men

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Answered by itzshivam15
3

Answer:

Number of days for which provisions last for 425 men= 30 days

Number of days for which provisions last for 1 men= 30×425

=12750 days. (less men means more days)

Number of days for which provisions last for 375 men= 12750/375

= 34 days

Hence, provisions will last for 34 days for 375 men.

Step-by-step explanation:

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