Question

In an army selection process, the ratio of selected to unselected candidates was 9:2. if 80 less had applied and 20 less selected, the ratio of selected to unselected would have been 5:1. how many candidates had applied for the process? एक आम???? क???? भत???? ????????

Answer 1

Let the total applicants be X

The selected = Y

Unselected = X - Y

The ratio of selected to Unselected is: 9:2

As per the unknowns this ratio is equal to :

Y:(X - Y) = 9:2

Y/(X - X) = 9/2

2Y = 9X - 9Y

11Y = 9X............i)


If there are 80 less applicants and 20 less selected then:

Total applicants =X - 80

Selected =Y - 20

Unselected = (X-80) - (Y - 20)
=X-Y-60

The ratio of selected to Unselected is : 5:1

This ratio is equal to:

(Y - 20) : (X - Y - 60)= 5:1

5/1 = (Y - 20)/(X - Y - 60)

5X - 5Y - 300 = Y - 20

6Y - 5X = - 280.........ii)

Solving equation i) and ii) simultaneously we have:

From i) Y =9/14X

Substituting this in ii) we have:

6 × 9/11X - 5X = - 280

-1/11X = - 280

X = (-280 × - 11)=3080

The total applicants are thus:

3080 candidates.

Answer 2

Answer:

3080

Step-by-step explanation:

Let the total applicants be x

Let the selected applicants be y

Thus Unselected applicants = x-y

We are given that The ratio of selected to Unselected is: 9:2

So,

y:(x-y) = 9:2

$\frac{y}{x-y}= \frac{9}{2}$

$2y = 9x - 9y$

$11y = 9x$ --1

We are given that there are 80 less applicants and 20 less selected then:

So,Total applicants =x - 80

Selected applicants =y - 20

Unselected applicants= (x-80) - (y - 20)=x-y-60

We are also given that The ratio of selected to Unselected is : 5:1

So,(y- 20) : (x-y- 60)= 5:1

$\frac{5}{1}= \frac{y - 20}{x-y-60}$

$6y-5x=-280$ --2

Solving equation 1 and 2

Substitute value of y from 1 in 2

$6\frac{9x}{11}-5x=-280$

$\frac{-x}{11}=-280$

$\frac{x}{11}=280$

$x=280 \times 11$

$x=3080$

Thus the total no. of applicants are 3080