Science, asked by TbiaSamishta, 10 months ago

In an astronomical telescope in normal adjustment a straight black line of length L is drawn on inside part of objective lens. The eye-piece forms a real image of this line. The length of the image is I. The magnification of the telescope is :

Answers

Answered by wasifthegreat786
2

=> M = L/I

Hope this helps you

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Answered by Arslankincsem
5

Answer:

The magnification of the telescope is L/I.The amplification of a cosmic telescope changes with the eyepiece utilized. It is determined by partitioning the central length of the telescope (normally set apart on the optical cylinder) by the central length of the eyepiece (both in millimeters). Accordingly:

TELESCOPE FOCAL LENGTH/OCULAR FOCAL LENGTH = MAGNIFICATION

For instance, a telescope with a 1000mm central length utilizing a 10mm visual is working at 100x amplification (1000/10=100).

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