Question

In an athematic progression 6th term is one more than twice the 3rd term the sum of 4 and 5 terms is 5 times the second term find the 10th term of the A.P

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Answer 1

Solution:

$a_6 = 1 + 2(a_3) \\ = 1 + 2(a + 2d) \\ = 1 + 2a + 2d \\ \\ a_4 + a_5 = 5(a_2) \\ a + 3d + a + 4d = 5a + 5d \\ 2a + 7d = 5a + 5d \\ 3a = 2d$

Answer 2

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