Question

In an atom the order of increasing energy of electrons with quantum numbers is
i) n = 4.1= 2
ii) n = 4.1=0
ii) n= 3, 1 = 2
iv) n = 3.1 = 1
a) ii<i<iv <ii
b) ii <iv <i< mi
c)i<iii <ii<iv
d) iv <i<i<i​

Answer 1

Answer:

n = 4.1 = 0 is the correct answer