in an attempt to prepare propane from wurtz reaction 1 mole of methyl bromide and 1 mole of ethyl bromide are treated with sodium. assuming equal probability of all possible reaction , how many gram of propane will be formed
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The reaction occurs with equal chances ( probability ).
1 mole of CH3Br and CH3CH2Br will form 1 / 3 of CH3CH2CH3 (propane).
The other products will be :
CH3Br + CH3CH2Br + 2 Na----------> CH3CH2CH3 + CH3CH2CH2CH3 + 2NaBr
One mol of CH3CH2CH3 = 44.0 g
Mass of CH3CH2CH3 = 44 / 3 = 14.67 g
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Answer:
44/3g of propane will formed
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