Math, asked by rekhaoviya2006, 19 hours ago

In an auditorium ,seats are arranged in rows and columns .The number
of rows were equal to the number of seats in each row .When the number
of rows were doubled and the number of seats in each row was reduced by
10,thetotalnumberofseatsincreasedby300.
Based on the above information ,answer the following questions: 5×1=
5
i)If x is taken as number of rows in original arrangement which of the following quadratic
equation describe the situation?
(a)x2−20x−300=0 (b)x2+20x−300=0
(c)x2−20x+300=0 (d)x2+20x+300=0
(ii)How many numbers of rows are there in the original arrangement?
(a)20 (b)40
(c)10 (d)30
(iii)Howmanynumbersofseatsarethereintheauditoriuminoriginalarrangement?
(a)725 (b)400
(c)900 (d)680
(iv)Howmanynumbersofseatsarethereintheauditoriumafterre-arrangement.
(a)860 (b)990
(c)1200

Answers

Answered by kanteepanks
0

Answer:

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Answered by NavyaRanjan
0

In an auditorium ,seats are arranged in rows and columns .The number

of rows were equal to the number of seats in each row

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