IN AN CERTAIN A.P.32th TERM IS TWICE THE 12th TERM . PROVE THAT 70th TERM IS TWICE THE 31st TERM
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Answer:
Let first term = a
let the difference = d
now,
T12 = a+11d
T32 = a+31d
now,
3(T12) = T32
》3a+33d = a+31d
》2a = -2d
》a = -d
now,
T31 = a+30d = -d+30d = 29d
T70 = a+69d = -d+69d = 68d
now,
2(T31) = 58d which is equal to T60
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