Question

In an election A got 42 votes out of 50 and B got 54 out of 60. who got higher percentage of votes?​

Answer 1

Answer:

B has 90% vote and A has 84% votes.

therefore B got higher percentage of vote

Step-by-step explanation:

$percentage \: of \: vote \: of \: a \\ = \frac{42}{50} \times 100\% \\ = 84\% \\ \\ of \: b \\ = \frac{54}{60} \times 100\% \\ = 90\%$

Answer 2

A=42/50×100%

A=84%votes

B=54/60×100%

B=90%votes

B got a higher percentage of votes..