Math, asked by Hdrnaqviiii9024, 1 year ago

In an election between two candidates, one gets 72% of the total votes. if the total votes are 8200, by how many votes did the winner win the election?

Answers

Answered by sumitsingh71
0
72*8200/100=5904 votes
the winner win the election
Answered by wifilethbridge
0

Answer:

3608

Step-by-step explanation:

One candidate got 72% votes

So, other candidate should got votes = 100% - 72% = 28%

So, The one who got 72% must be the winner

Total votes = 8200

Winner votes = 72% of 8200

                       =\frac{72}{100} \times 8200

                       =5904

loser votes = 28% of 8200

                  =\frac{28}{100} \times 8200

                  =2296

Difference in votes = 5904-2296 =  3608

Hence the winner win the election by 3608 .

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