Math, asked by ambertanweer1453, 1 year ago

In an election between two candidates one got 72% of total votes .if total votes are 8200 by how many votes did winner win election?

Answers

Answered by ayush2883
0
winner candidates is win by 5904 votes . total votes are 8200and one candidate who got 72percent is winner.8200*72/100=5904
Answered by wifilethbridge
1

Answer:

Winner win election by 3608 votes.

Step-by-step explanation:

One candidate got votes = 72%

Other candidate got votes = 100%- 72 % = 28%

So, The winner must be the candidate who got 72% votes

Total votes =8200

No. of votes of winner candidate = 72\% \times 8200

                                                      = \frac{72}{100} \times 8200

                                                      = 5904  

No. of votes of loser candidate = 28\% \times 8200

                                                      = \frac{28}{100} \times 8200

                                                      = 2296  

Difference in votes = 5904-2296

                                =3608

Hence winner win election by 3608 votes.

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