Question

In an election, candidate A has secured 12% votes more than candidate B. By how much per cent has candidate B less than candidate A?

Answer 1

Hello friend☆

Let take seats of B be x

A= x+12x/100

A=112x/100= 56x/50= 28x/25

Peecenta B less than A

(28x/25 - x)/28x/25 ×100

3x/ 25 ×25/28x ×100

300/28%= 150/14%= 75/7%= 10 whole 5 by 7 %

Answer 2

Answer:

Step-by-step explanation:

Let take seats of B be x

A= x+12x/100

A=112x/100= 56x/50= 28x/25

Peecenta B less than A

(28x/25 - x)/28x/25 ×100

3x/ 25 ×25/28x ×100

300/28%= 150/14%= 75/7%= 10 whole 5 by 7 %

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