Question

In an election, candidate A has secured 12% votes more than candidate B. By how much per cent has candidate B less than candidate A?
answer with explanation please

Answer 1

3/25x  

Step-by-step

let the no of votes by candidate B be x.so the number of votes by candidate A will be 12% of x ,

12/100*x=number of votes  by A.

Answer 2

Answer:

Given: In an election candidate, A had secured 12% vote more than candidate B.

To find: We have to find by how much per cent had candidate B less than candidate A.

Solution:

To determine the by how much per cent had candidate B less than candidate A we have to follow the below steps-

Let B has secured 100 votes.

A had secured 12% vote more than candidate B.

Thus A has secured 100+12=112 votes.

Thus the percentage of votes B gets less than A is given as-

\begin{gathered} \frac{112 - 100}{112} \times 100 \\ = 10.71\end{gathered}

112

112−100

×100

=10.71

Thus by 10.71% candidate B had secured fewer votes than candidate A.