Math, asked by faizanmoin149, 1 year ago

In an election of housing society there are 30 voters each of them gives the vote three persons x y and z are standing for the past of secretary if mr x got 2/5 of the total votes and mr z got 1/3 of the total votes then find the number of votes which mr y got

Answers

Answered by amitnrw
3

Answer:

Mr Y got 8 votes

Step-by-step explanation:

n an election of housing society there are 30 voters each of them gives the vote three persons x y and z are standing for the past of secretary if mr x got 2/5 of the total votes and mr z got 1/3 of the total votes then find the number of votes which mr y got

Total number of Votes = 30

Mr X got = (2/5) * 30  = 12 Votes

Mr. Z got = (1/3) * 30 = 10 Votes

Mr Y got = 30 -12 - 10 = 8 Votes

or

Mr Y got  = 1 - 2/5 - 1/3

= (1/15) ( 15 - 6 - 5)

= 4/15

4/15 of 30

= (4/15) * 30

= 8 Votes

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