In an election of housing society there are 30 voters each of them gives the vote three persons x y and z are standing for the past of secretary if mr x got 2/5 of the total votes and mr z got 1/3 of the total votes then find the number of votes which mr y got
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Answered by
11
2/5 of 30 is 12 and 1/3 of 30 is 10 it's total is 22 and total voters are 30 then mr y got 8 votes
Answered by
26
The total number of voters is 30.
So, number of votes won by x is 2/5 of total votes .
Therefore , votes won by x = 2/5 of 30
= 2/5 × 30
= 2×6
= 12 votes.
Number of votes won by z is 1/3 of total votes.
Therefore, votes won by z = 1/3 of 30
= 1/3 ×30
= 30/3
= 10
Number if votes won by x is 12 and z is 10.
So, number of votes won by y will be =
(Total number of votes) -(number of votes won by x and z)
y = 30 - ( 12+10)
y = 30 - 22
y = 8
Answer) Number if votes won by Mr. y is 8.
So, number of votes won by x is 2/5 of total votes .
Therefore , votes won by x = 2/5 of 30
= 2/5 × 30
= 2×6
= 12 votes.
Number of votes won by z is 1/3 of total votes.
Therefore, votes won by z = 1/3 of 30
= 1/3 ×30
= 30/3
= 10
Number if votes won by x is 12 and z is 10.
So, number of votes won by y will be =
(Total number of votes) -(number of votes won by x and z)
y = 30 - ( 12+10)
y = 30 - 22
y = 8
Answer) Number if votes won by Mr. y is 8.
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