Question

In an election of housing society there are 30 voters each of them gives the vote three persons x y and z are standing for the past of secretary if mr x got 2/5 of the total votes and mr z got 1/3 of the total votes then find the number of votes which mr y got

Answer 1

The total number of voters is 30.

So, number of votes won by x is 2/5 of total votes .

Therefore , votes won by x = 2/5 of 30

= 2/5 × 30

= 2×6

= 12 votes.

Number of votes won by z is 1/3 of total votes.

Therefore, votes won by z = 1/3 of 30

= 1/3 ×30

= 30/3

= 10

Number if votes won by x is 12 and z is 10.

So, number of votes won by y will be =
(Total number of votes) -(number of votes won by x and z)

y = 30 - ( 12+10)

y = 30 - 22

y = 8

Answer) Number if votes won by Mr. y is 8.

Answer 2

x+y+z=30

x=2/5, y=?, z=1/3

2/5+y+1/3=30

6/15+y+5/15=30

11/15+y=30

y=30-11/15

y=450-11/15

y=439/15