Political Science, asked by Manisuman1635, 1 year ago

"in an election survey, 83 13% of total voterstook part in survey, 50% then claims tovotes for candidate a, 10% are uncertain &rest says to vote for



b. If all of them votedaccording to their commitments on the dayof election and those who were not part ofsurvey, voted to a and b in ratio of 2:1. Allthe people who are uncertain in survey,voted to a:b in the ratio of 1:4 in election.If a won by 640 votes then find totalnumber of votes in election.

Answers

Answered by laxmi8270
0

Answer:

it's hard to conduct 1st election

Answered by deepakkumar024
4

7200

Explanation:

ated in survey=83 1/3% of (250/3 )/100=250/300=5X/6

Not participated=x/6

A=50%(5x/6)=2.5x/6

Un certain=0.5x/6

B=2x/6

Not in survey A=2/3 *X/6=X/9

NOT IN SURVEY B=1/3 *X/6=X/18

Un certain A = 1/5 * 0.5x/6=0.1x/6

Un certain B= 4/5*0.5x/6=0.4x/6

A= 2.5x/6 + x/9 + 0.1x/6= =7.5X+2X+0.3X/189.8X/18

B=2x/6 + x/18 + 0.4x/6= 6X+X+1.2X/188.2X/18

A-B=640

1.6X/18 =640

X=7200

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