Question

in an election the supporters of two candidates Aand B were taken to polling booth in two different vehicles, capable of carrying 10 and 15 voters
respectively. If at least 90 vehicles were required to
carry a total of 1200 voters, then find the maxi-
mum number of votes by which the elections
could be won by the Candidate B.
ANS .600 .........,...........
SPAMS WILL BE REPORTED
BRAINLIEST YR ANS... AWARDED​

Answer 1

Answer:-

• The total number of voters = 1200.

• The vehicle of candidate A can carry 10 voters per vehicle.

• The vehicle of candidate B can carry 15 voters per vehicle.

• The total number of vehicles = 90.

Let the total number of vehicles with candidate A be x and the total number of vehicles with the candidate B be 90 - x.

Now, we are already given a number of voters per vehicle.

So, For candidate A = 10x is the number of voters.

And for candidate B = 15(90 - x) is the total number of voters.

Now, we are given that the total number of voters is 1200.

So, according to the information given in the question,

➜ 10x + 15(90 - x) = 1200

➜ 10x + 1350 - 15x = 1200

➜ 1350 - 5x = 1200

➜ 1350 - 1200 = 5x

➜ 5x = 150

➜ x = 150/5

➜ x = 30

Now, finding the total number of voters of candidate A = 10x = 10 × 30 = 300 voters.

And the total number of voters of candidate B = 15(90 - x) = 15(90 - 30) = 15 × 60 = 900 voters.

Now, the question ask us the number of votes by which candidate B won the election.

So, 900 - 300 = 600 votes is the Answer.

$\rule{200}2$

Answer 2

AnswEr :

600.

$\bf{\red{\underline{\underline{\bf{Given\::}}}}}$

In an election the supporters of two candidates A and B were taken to polling both in two different vehicles, capable of carrying 10 and 15 voters respectively. If at least 90 vehicles were required to carry a total of 1200 voters.

$\bf{\red{\underline{\underline{\bf{To\:find\::}}}}}$

The maximum number of votes by which the elections could be won by the candidate B.

$\bf{\red{\underline{\underline{\bf{Explanation\::}}}}}$

$\bf{We\:have}\begin{cases}\sf{Two\:candidates\:A\:and\:B}\\ \sf{Total\:vehicles\:=90}\\ \sf{Total\:Voteres\:=1200\:voters}\end{cases}}$

A/q

$\leadsto\sf{A+B=90}\\\\\leadsto\sf{\green{A=90-B.................(1)}}$

Now;

$\leadsto\sf{10A + 15B=1200}\\\\\leadsto\sf{10(90-B)+15B=1200\:\:\:\:\:\:\big[from(1)\big]}\\\\\leadsto\sf{900-10B+15B=1200}\\\\\leadsto\sf{900+5B=1200}\\\\\leadsto\sf{5B=1200-900}\\\\\leadsto\sf{5B=300}\\\\\leadsto\sf{B=\cancel{\dfrac{300}{5} }}\\\\\leadsto\sf{\red{B=60\:vehicles}}$

$\star$ Putting the value of B in equation (1), we get;

$\leadsto\sf{A=90-60}\\\\\leadsto\sf{\red{A=30\:Vehicles}}$

$\star$ Required number of votes :

$\mapsto\sf{A=10(30)=\green{300\:votes.}}\\\\\mapsto\sf{B=15(60)=\green{900\:votes.}}$

$\star$ Number of votes required which by won the candidate B :

$\leadsto\sf{Candidate\:(B)\:of\:votes-Candidate\:(A)\:of\:votes}\\\\\leadsto\sf{900\:-\:300}\\\\\leadsto\sf{\green{600\:votes\:required.}}$