Question

In an election, there are three candidates A, B, C. Candidate A gets 48% votes which are 40 more than C and 70 more than B. if B gets 20% votes then how
number of votes C get?
​

Answer 1

Answer:

80

Step-by-step explanation:

ABC =48%,20%,32% resp

thus A-B=28%=70

Thus 32%=80

Answer 2

Given: In an election, there are three candidates A, B, C. Candidate A gets 48% votes which are 40 more than C and 70 more than B.

To find: We have to find the number of votes C get.

Solution:

Let the total number of vote is x.

A get 48% of votes mean $\dfrac{48x}{100}$ votes.

So, this votes of A is 40 more than C and 70 more than B.

So, we can write number of votes of C is

$\frac{48x}{100} - 40$

Number of votes of B is

$\frac{48x}{100} - 70$

Now given that B gets 20% votes mean $\dfrac{20x}{100}$ votes.

We can write-

$\frac{48x}{100} - 70 = \frac{20x}{100} \\ \frac{48x}{100}-\frac{20x}{100} = 70 \\ \frac{28x}{100} = 70 \\ x = 70 \times \frac{100}{28} \\ x = 250$

C gets-

$\frac{48 \times 250}{100} - 40 \\ = 120 - 40 \\ = 80$

So, C gets 80 votes.