in an election, there are two candidates A and B contesting from a constituency total number of voters in this constituency is 65500 out of which only 70% votes are polled. If 54% of the polled votes were cast in favor of B, how many votes did A get?
Answers
Answered by
0
Answer:
Votes polled = 80% of 60000
i.e 80/100*60000
=48000
Votes received by B is 100%- 60%
=40%
therefore votes received by B is 40/100 * 48000
=19200
Answered by
1
Answer:
Total number of votes=60000
Percentage of total votes polled=80% of 60000=80/100*60000=48000
Votes polled for A=60% of 48000=60/100*48000=28800
Votes received by B=48000-28800=19200 ans...
HOPE THIS HELPS YOU
PLZZ MARK AS BRAINLIEST
Similar questions