Question

In an election, there were two candidates A and B. 80% of the total votes of 6000 were polled. If 60% of the polled votes were cast in favour of A, find the number of votes cast in favour of B.​

Answer 1

Step-by-step explanation:

Total no. of votes polled=80/100 × 6000= 4800

No.of votes candidate A got = 60/100 × 4800 =2880

No.of votes candidate B got = 4800-2880=1920

Let the total percent of votes polled be 100%

: . Pecent of votes candidate B got= 100-60= 40%