Question

In an election there were two candidates A and B. The total number of voters in this constituency was 60000 and 80% of the total votes were polled. If 60% of the polled votes were cast in favour of A, how many votes were received by B.

Answer 1

Answer:

21200

Step-by-step explanation:

Total number of voters were 60000.

Out of them only 80% votes polled.

So number of votes polled= 60000×80/100

=48000

So the number of votes polled are 48000.

Out of them 60% of the votes were casted in favour of A.

So number of votes casted in favour of A are=48000×60/100

=28800

So the number of votes casted in favour of A are 28800.

So the number of votes casted in favour of B are=48000-28800

=21200