Question

in an election there were two candidates . The winner obtained 56% votes and won by 8400 votes. Find the total number of votes polled

Answer 1

Step-by-step explanation:

candidate one = 56% vote

candidate two = 44% vote

56% - 44% = 12%

x = (8400*100)/12

total votes (x) = 70000

Answer 2

The total number of votes polled is 70000

Step-by-step explanation:

Let the total no. of votes polled be x

We are given that The winner obtained 56% votes and won by 8400 votes.

So, Loser votes percentage = 100%-56% =44%

Winner votes = $56\%x = 0.56x$

Loser votes = $44\%x = 0.44x$

So, ATQ

$0.56x- 0.44x=8400$

$0.12x=8400$

$x=\frac{8400}{0.12}$

$x=70000$

Hence the total number of votes polled is 70000

#Learn more:

In an election there were only two candidates. The winner polled 55% votes and won by a margin of 8756 votes. Find the total number of votes polled.

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